Question

if 2 opposite vertices of square are (7,-3) and (-1,11) find equations of its diagonals​

Answer 1

Answer:

$7x + 4y - 37 = 0$

Step-by-step explanation:

A(7,-3)
B(-1 , 11)

$m= \frac{(y_{2} - y_{1} )}{(x_{2} - x_{1} )}$
$m= \frac{11+3}{-1-7} \\ m = \frac{14}{-8}$
$m = \frac{7}{-4}$

Now we find the equation:
$y - y_{1} = m ( x - x_{1} )\\ y+3=\frac{-7}{4} (x - 7)\\ 4y+12=-7x-49\\ 4y+7x+12-49=0\\ 7x + 4y - 37 = 0$


Hope the answer helped
Thankyou

Answer 2

7x+4y-37=0

Step-by-step explanation:

7x+4y-37=0