Question

if 2(p^2+q^2)=(p+q)^2 show that p= q​

Answer 1

Step-by-step explanation:

2(p^2+q^2)=(p+q)^2

2p^2+2q^2=p^2+q^2+2pq

p^2+q^2=2pq

p^2+q^2-2pq=0

(p-q)^2=0

p-q=0

p=q

Hence proved