if 2^p.3^q.5^r=60, then which of the following is true? Given; p,q,r are natural numbers. a: p+q+r=3. b: p=q=r. c:p=2,q=r=1. d:p+q+r= 0
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Answer: Option (c)
Step-by-step explanation: factorising 60, we get,
60=2^2 (3) (5)
So, p=2, q=1, r=1
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