Math, asked by kumkumsharma1, 8 months ago

if 2^p.3^q.5^r=60, then which of the following is true? Given; p,q,r are natural numbers. a: p+q+r=3. b: p=q=r. c:p=2,q=r=1. d:p+q+r= 0​

Answers

Answered by Sid3412
2

Answer: Option (c)

Step-by-step explanation: factorising 60, we get,

60=2^2 (3) (5)

So, p=2, q=1, r=1

Answered by bharatsingh831854
0

Answer:

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