Question

if 2,p,6,q are in ap then p-q is ...........

Answer 1

Answer:

p-q=(-4)

Step-by-step explanation:

Given:-

AP:-2,p,6,q where a=2.

To Find:-

The value of p-q.

Formula Applied:-

$a_n = a + (n - 1) \times d$

Solution:-

$a = 2 \: and \: a_3 = 6$

$a_3 = 6$

$6 = a + (3 - 1) \times d$

$6 = 2 + 2d$

$6 - 2 = 2d$

$4 = 2d$

$d = \frac{4}{2}$

$d = 2$

$a_2 = p$

$p = a + (2 -1 ) \times d$

$p = 2 + 2$

$p = 4$

$a_4 = q$

$q = a + (4 - 1) \times d$

$q = 2 + (3) \times (2)$

$q = 2 + 6$

$q = 8$

Now we have to find p-q,

→p-q=4-8

→p-q=(-4)

Answer 2

Answer:

Hey mate.....

p - q = - 4.....

please mark as brainlest...