if 2 point charges Q1 ,Q2 exert a force F on each other when kept certain distance apart . if the charge on each particle is halfed and the distance between 2 particals doubled ,then the new force between 2 particles would be
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Answer:
The new force between 2 particles would be 1/16 times than the original force.
Explanation:
We know that the force between 2 charged particles is given by,
F = k x Q₁Q₂/r²
Hence the force between them is directly proportional to product of the charges and inversely proportional to the square of the distance between them,
when the charges becomes half and distance doubled, the new force will be given by,
F' = k x (Q₁/2)(Q₂/2)/(2r)₂
= k x Q₁Q₂/r² x 1/16
=> F' = F/16
Hence the new force between 2 particles would be 1/16 times than the original force.
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