Question

if 2 power x =256 and 3power y= 81 then find value of log x base 2+log y base2

Answer 1

$2 {}^{x} = 256 \\ 256 = 2 {}^{8} \\ x = 8$
$log_{2}(x) + log_{2}(y) \\ log_{2}(xy) = log_{2}(4 \times 8) \\ log_{2}(32) = log_{2}(2 {}^{5} )$

$3 {}^{y} = 81 \\ 81 = 3 {}^{4} \\ y = 4$
answer 5