if 2 power x = 3 power y = 6 power z , show that z = xy / x+y(pls ans within 20 mins because it is very urgent )
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2^x = 3^y = 6^z
2^x = 6^z
Raise both sides to power y.
2^{xy} = 6^{zy} --- (1)
3^y = 6^z
Raise both sides to power x
3^{xy} = 6^{xz} --- (2)
multiply (1) and (2)
=> (2 * 3)^{x y} = 6^{z y + x z} = 6^{z(x+y)}
=> 6^{x y} = 6^{z(x+y)}
=> x y = z(x+y)
=> z = (x y) / (x + y)
2^x = 6^z
Raise both sides to power y.
2^{xy} = 6^{zy} --- (1)
3^y = 6^z
Raise both sides to power x
3^{xy} = 6^{xz} --- (2)
multiply (1) and (2)
=> (2 * 3)^{x y} = 6^{z y + x z} = 6^{z(x+y)}
=> 6^{x y} = 6^{z(x+y)}
=> x y = z(x+y)
=> z = (x y) / (x + y)
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