if 2 power6×5power3×x = 2 power12 find x
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(2)6 × (5)3 × X = (2)12
(2×2×2×2×2×2 ) × (5×5×5) × X = 2×2×2×2×2×2×2×2×2×2×2×2
64 × 125 × X = 4096
800 × X = 4096
X = 4096 / 800
X = 5.12
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