If 2 raised to the power a = 3 raised to the power b = 6 raised to the power c, then the value of c is?
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Answer:
c= ab/a+b
Step-by-step explanation:
Let 2^a=3^b=6^c =k
2 = k^(1/a), 3 = k^(1/b) and 6= k^(1/c)
2*3=6
k^(1/a)*k^(1/b) = k^(1/c)
k^(1/a +a/b)= k^(1/c)
1/a +a/b = 1/c
a+b/ab = 1/c
c= ab/a+b
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