Question

If 2- root 3 is a root of the quadratic equation x^2+2(root3-1)x+3-2root3,then the second root is

Answer 1

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Answer 2

The second root is $-\sqrt{3}$.

Step-by-step explanation:

If a equation is defined as $ax^2+bx+c=0$, then

The sum of roots = -b/a

The given equation is

$x^{2}+2(\sqrt{3}-1)x+3-2\sqrt{3}$

Here, $a=1,b=2(\sqrt{3}-1),c=3-2\sqrt{3}$

$2-\sqrt{3}$ is  root of the given quadratic equation. Let p is the other root of this equation.

$2-\sqrt{3}+p=-\dfrac{2(\sqrt{3}-1)}{1}$

$2-\sqrt{3}+p=-2\sqrt{3}+2$

$p=-2\sqrt{3}+2-2+\sqrt{3}$

$p=-\sqrt{3}$

Therefore, the second root is $-\sqrt{3}$.

#Learn more

Find value of k so that the sum of root of quadratic equation 3x^2 + (2k+1)x + 5 - k = 0 is equal to the product of roots.

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