Math, asked by Anonymous, 1 year ago

If 2,root 8,4,.......in g.p,then the common ratio is...with procedure​

Answers

Answered by daraharshini9
2

Answer:

HI MATE......

HERE IS YOUR ANSWER...

Step-by-step explanation:

In mathematics, a geometric progression(sequence) (also inaccurately known as a geometric series) is a sequence of numbers such that the quotient of any two successive members of the sequence is a constant called the common ratio of the sequence.

The geometric progression can be written as:

ar0=a, ar1=ar, ar2, ar3, ...

where r ≠ 0, r is the common ratio and a is a scale factor(also the first term).

Examples

A geometric progression with common ratio 2 and scale factor 1 is

1, 2, 4, 8, 16, 32...

A geometric sequence with common ratio 3 and scale factor 4 is

4, 12, 36, 108, 324...

A geometric progression with common ratio -1 and scale factor 5 is

5, -5, 5, -5, 5, -5,...

Formulas

Formula for the n-th term can be defined as:

an = an-1⋅r

an = a1⋅rn-1

Formula for the common ratio is:

r =

ak

ak-1

If the common ratio is:

Negative, the results will alternate between positive and negative.

Example:

1, -2, 4, -8, 16, -32... - the common ratio is -2 and the first term is 1.

Greater than 1, there will be exponential growth towards infinity (positive).

Example:

1, 5, 25, 125, 625 ... - the common ratio is 5.

Less than -1, there will be exponential growth towards infinity (positive and negative).

Example:

1, -5, 25, -125, 625, -3125, 15625, -78125, 390625, -1953125 ... - the common ratio is -5.

Between 1 and -1, there will be exponential decay towards zero.

Example:

4, 2, 1, 0.5, 0.25, 0.125, 0.0625 ... - the common ratio is \displaystyle \frac{1}{2}

2

1

4, -2, 1, -0.5, 0.25, -0.125, 0.0625 ... - the common ratio is \displaystyle -\frac{1}{2}−

2

1

.

Zero, the results will remain at zero.

Example:

4, 0, 0, 0, 0 ... - the common ratio is 0 and the first term is 4.

Geometric Progression Properties

a2k = ak-1⋅ak+1

a1⋅an = a2⋅an-1 =...= ak⋅an-k+1

Formula for the sum of the first n numbers of a geometric series

Sn =

a1 - anr

1 - r

= a1.

1 - rn

1 - r

Infinite geometric series where |r| < 1

If |r| < 1 then an -> 0, when n -> ∞.

The sum S of such an infinite geometric series is given by the formula:

S = a1

1

1 - r

which is valid only when |r| < 1.

a1 is the first term.

Answered by loya1
3

given 2,√8,4 are in gp then r=(√8)/2=√2

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