IF 2-ROOT OF 3,THEN FIND THE VALUE OF X^2+1/X^2
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Answer:
As x= 2+30.5
then x - 1/x = 2+30.5 - 1/2+30.5
Then take L.C.M.
= [ (2+30.3)2+1 ] / 2+30.5
= [ 6+4root3] / 2+root3
Then Rationalise the Denomenator
=[(6+4root3)(2-root3)] / [(2+root3)(2-root3)]
=[12-6root3+8root3-12] / [4-3]
= 2root3 /1
Answer = 2root3
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