if 2 sides of a pair of opposite sides of a cyclic quadrilateral are equal prove that its diagonal are equal
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AD=BC
AC and BD are diagonals of cyclic quadrilateral.
In △AOD and △BOC
⇒ ∠OAD=∠OBC [ Same segment subtends equal angle to the circle ]
⇒ AD=BC [ Given ]
⇒ ∠ODA=∠OCB [ Same segment subtends equal angle to the circle ]
∴ △AOD≅△BOC [ By ASA congruence rule ]
Adding △DOC on both sides, we get
⇒ △AOD+△DOC≅△BOC+△DOC
⇒ △ADC≅△BCD
⇒ AC=BD [ By CPCT ]
Hence, we have proved that, a pair of opposite sides of a cyclic quadrilateral are equal prove that its diagonals are also equal
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