If (2 sin 0+3 cos 0) = 2, prove that (3 sin 0-2 cos 0)=+-3.
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Answer:
value of sin 0=1
value of cos 0=0
(2sin0+3cos0)=2×1+3×0=2
(3sin0-2cos0)=3×1-2×0=3 HENCE PROVED.
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