Question

If √2 sinΦ = 1, find the value of sec²Φ - cosec²Φ.​

Answer 1

Answer:

sin theta = 1/ root2 = sin 45°

sec² theta - cosec² theta = 2 - 2 =0

Answer 2

Step-by-step explanation:

√2 sinΦ = 1

sinΦ = 1/√2

SinΦ = sin1/√2

sinΦ = sin45° [since sin45° = 1/√2]

Cancelling sin from both sides.

Φ = 45°

therefore,

sec²45°—cosec²45°

= (√2)²—(√2)²

= 2—2

= 0

....Hence,the value of sec²Φ—cosec²Φ is 0.

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