Question

if 2 sin 2 theta + 3 cos 2 theta = 4 show that tan theta = 1/√3​

Answer 1

Answer:

4sin2θ+3(sin2θ+cos2θ)=4

4sin2θ+3=4

4sin2θ=1⇒sinθ=21

AC2=AB2+BC2

4−1=AB⇒AB=3

tanθ=BABC=31