If 2.sin 2 theta=√3, then prove that
3 cot^2 theta - 2 sin theta =8
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Answered by
6
Answer:
I'll be using A instead of theta, if that's not a problem.
Given: 2sin2A = √3
=> sin2A = √3/2
But sin60° = √3/2
So,
sin2A = sin60°
=> 2A = 60°
=> A = 60/2 = 30°
R.T.P: 3cot²A -2sinA = 8
=> 3cot²30° - 2sin30° = 8
=> 3(√3)² - 2(1/2) = 8
=> 3(3) - 1 = 8
=> 9 - 1 = 8
=> 8 = 8
Hence Proved.
Answered by
0
Answer:
8
Step-by-step explanation:
the answer is 8 u can check in the paper which is top
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