if 2 sin^2 theta -cos^2 theta= 2 find the value of theta. plz ......solve this question
Barbiesofia:
plz.... solve this question on paper
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Answered by
219
From the question,
2 sin²Θ - cos²Θ = 2
2 sin²Θ - 2 = cos²Θ
From the Identity ⇒ sin²Θ + cos²Θ = 1
2(sin²Θ - 1) = cos²Θ
2(- cos²Θ) = cos²Θ
- 2 cos²Θ = cos²Θ
3 cos²Θ = 0
cos²Θ = 0
From the Trigonometric table cos 90° = 0 ⇒ cos² 90° = 0
Then, cos²Θ = cos² 90°
Cancelling cos²Θ on both sides,
Θ = 90°
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☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
2 sin²Θ - cos²Θ = 2
2 sin²Θ - 2 = cos²Θ
From the Identity ⇒ sin²Θ + cos²Θ = 1
2(sin²Θ - 1) = cos²Θ
2(- cos²Θ) = cos²Θ
- 2 cos²Θ = cos²Θ
3 cos²Θ = 0
cos²Θ = 0
From the Trigonometric table cos 90° = 0 ⇒ cos² 90° = 0
Then, cos²Θ = cos² 90°
Cancelling cos²Θ on both sides,
Θ = 90°
______________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
Answered by
47
I hope it helps you my friend
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