Question

If 2 sin (3x - 15°) = √3,

then find the value of sin^2 (2x + 10)° + tan^2(x + 5)°.

Answer 1

Heya !!

Here's ur answer !

Given 2 sin (3x -15)° = √3

$\bold = sin(3x - 15)\degree \: = \frac{ \sqrt{3} }{2} = \\ sin(3x - 15) \degree = sin \: 60 \degree \\ = 3x - 15 = 60 = 3x = 75 = x = 25. \\ \therefore \: {sin}^{2} (2x - 10) \degree + {tan}^{2} (x + 5) \degree \\ = {sin}^{2} 60 \degree \: + {tan}^{2} 30 \degree \\ = (\frac{ \sqrt{3} }{2} )^{2} + ( \frac{1}{ \sqrt{3} } )^{2} = \frac{3}{4} + \frac{1}{3} \\ = \frac{9 + 4}{12} = \frac{13}{12}.$
Glad help uh !

thanks .

Answer 2

Step-by-step explanation:

Hey dear ‼️

==> 13/12 is your answer..

keep loving....❤️❤️❤️❤️❤️✌️