If 2 sin A = 1
√2 cos B = -1
A lies in 2nd quadrant
B lies in 3rd quadrant
Find :
tan A + tan B
-------------------
cos A - cos B
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Answer:
sinA = 1/2
sinA = sin 30°
A=30°
cos B= - (1/√2)
cosB = cos 225°
B = 225°
tan 30° + tan 225° / cos 30 ° - cos 225°
1/√3 + 1/ √3/2 - (-1/√2)
(√3+1) /√3 / (√6+ 2) /2√2
please mark as a brainlist
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