if 2×sin square theta - cos square theta =2,find theta
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consider the identity,
cos²θ + sin²θ = 1
given,
2×sin²θ - cos²θ =2
2×sin²θ -1 + sin²θ = 2
sin²θ = 1
sinθ = ±1
so θ = (2n-1)π/2
cos²θ + sin²θ = 1
given,
2×sin²θ - cos²θ =2
2×sin²θ -1 + sin²θ = 2
sin²θ = 1
sinθ = ±1
so θ = (2n-1)π/2
Answered by
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this is the right answer
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