Question

If 2 sin theta = √3, then cot theta = ? ​

Answer 1

Answer:

Step-by-step explanation:

Suppose a triangle ABC in which theta=<C

AB=√3 and AC=2

2sin theta= √3

So, sin theta = √3/2 = AB/AC

So, AB= √3 and AC= 2

By Pythagoras' Theorem

BC^2=AC^2 - AB^2

BC^2= (2)^2 - (√3)^2

BC^2= 4 - 3

BC^2= 1

BC = √1=1

Therefore, cot theta= BC/AB = 1/√3