Question

if 2 sin theta -4cos theta =0 then find tan^2theta +1/sec theta give me answer please ​

Answer 1

Answer:

Step-by-step explanation:

p  

2

−1

​

 

=  

(secθ+tanθ)  

2

+1

(secθ+tanθ)  

2

−1

​

 

sec  

2

θ+tan  

2

θ+2secθtanθ+1

sec  

2

θ+tan  

2

θ+2secθtanθ−1

​

 

=  

sec  

2

θ+(tan  

2

θ+1)+2secθtanθ

(sec  

2

θ−1)+tan  

2

θ+2secθtanθ

​

 

=  

sec  

2

θ+sec  

2

θ+2secθtanθ

tan  

2

θ+tan  

2

θ+2secθtanθ

​

 

=  

2sec  

2

θ+2secθtanθ

2tan  

2

θ+2secθtanθ

​

 

=  

2secθ(secθ+tanθ)

2tanθ(tanθ+secθ)

​

 

=  

2secθ

2tanθ

​

 

=tanθ×cosθ

=  

cosθ

sinθ

​

×cosθ

=sinθ

Answer 2

Answer:

$2 \sin( \alpha ) - 4 \cos( \alpha ) = 0 \\ \sin( \alpha ) - 2 \cos( \alpha ) = 0 \\ \tan( \alpha ) = 2 \\ \\ now \\ \\ { \tan( \alpha ) }^{2} + \ \ \frac{1}{ \sqrt{ \ { \tan( \alpha ) }^{2} } } \\ 4 + \frac{1}{ \sqrt{5} } \\ = 4.4472$