Question

If 2 sin theta=underroot 3 then find .a)cos theta b)tan theta c)cot theta +cosec theta​

Answer 1

2 sin A = √3

sin A=√3/2. (A=theta)

so we know that

opposite side =√3 ,hypotenuse =2

"by phthagrous theorm"

adj = √*(hyp)^2 -(opo)^2

adj =√(2)^2 -(√3)^2

adj=√4 - 3

adj =√1

adj =1

adjacent side = 1

so we know all sides

(a) cos A = adjacent side/hypotenuse

cosA=. 1/2

(b)tan A =opposite side/adjacent side

tan A =√3/1

(c) cot A + cosec A =1/√3 + 2 /√3

cot A + cosec A =1+2/√3

cot A + cosec A=3/√3

cot A + cosec A=√3

hence proved

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Answer 2

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