Question

if 2 sin x + cos x = 7/3 then tan² x - sec² x =?​

Answer 1

Step-by-step explanation:

we know that

sin²x+cos²x= 1

on dividing both side by cos²x

(sin²x/cos²x)+(cos²x/cos²x)= 1/cos²x

tan²x+1=sex²x

tan²x - sec²x+1=0

tan²x - sec²x= -1

or

we know that,

1+tan²∅= sec²∅

1+tan²∅-sec²∅=0

tan²∅-sec²∅= -1

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