Question

If √2 sinA=1, then find the value of sec²A-cosec²A

Answer 1

Answer:

0

Step-by-step explanation:

1. sinA=1/√2
2. sinA=sin45°
3. A=45°

therefore

1. sec²45°-cosec²45°
2. (√2)²-(√2)²
3. 2-2=0

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Answer 2

Sol: Given :- √2sinA = 1

⟹sinA = 1/√2

⟹SinA = sin45 [∵ Sin45° = 1/√2]

∴ A = 45°

Now we have to find value of sec²A-cosec²A

sec²(45°)-cosec²(45°)

⟹ (√2)²-( √2)²

⟹ 2-2 = 0

[∵ sec²45°= √2 and cosec²45 ° = √2 ]

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