Question

If 2 sinx= 1,x/2{x{π and √2cosy =1,3×π/2{y{2π find the value of tanx+tany/cosx-cosy
please give me answer​

Answer 1

Step-by-step explanation:

sinx = 1/2

cosx = -√3/2

siny = -1/√2

cosy = 1/√2

Now just plug in your values:

(-1/√3 - 1)/(-√3/2 - 1/√2) =

I'll let you massage that to a more pleasant appearance.

Answer 2

sinx = 1/2

cosx = -√3/2

siny = -1/√2

cosy = 1/√2

Now just plug in your values:

(-1/√3 - 1)/(-√3/2 - 1/√2) =

I'll let you massage that to a more pleasant appearance.