if 2 tan theta = √2 sec theta find 1) theta 2) sin ^2 theta - cos ^2 theta
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Answer: 2 tan Ф =√2
or, tan Ф =1/√2
i) Ф = 45°
ii) sin^2 Ф - cos^2 Ф = (sin 45°)² - (cos 45°)² = (1/√2 )² - (1/√2 )² = 0
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