if 2^x+1=3^1-x find value of x
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Answer:
Here is your answer brother :
x=log↓2(3)-1/1+log↓2(3)
Step-by-step explanation:
now,
2^x+1=3^1-x
Taking log base 2 on both sides
→(x+1) log↓2 (2) = (1-x) log↓2 (3)
→ (x+1)= log↓2 (3)- x.log↓2(3)
→x[1+log↓2 (3)] = log↓2 (3) -1
→x = log↓2 (3)-1/1+ log↓2 (3)
<I HOPE THIS WILL HELP YOU>
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