Math, asked by Karivadan, 10 months ago

if 2^x+1=3^1-x find value of x​

Answers

Answered by aassemble4
3

Answer:

Here is your answer brother :

x=log↓2(3)-1/1+log↓2(3)

Step-by-step explanation:

now,

2^x+1=3^1-x

Taking log base 2 on both sides

→(x+1) log↓2 (2) = (1-x) log↓2 (3)

→ (x+1)= log↓2 (3)- x.log↓2(3)

→x[1+log↓2 (3)] = log↓2 (3) -1

→x = log↓2 (3)-1/1+ log↓2 (3)

<I HOPE THIS WILL HELP YOU>

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