Question

If 2^x+1=3^1-x then find the value of x​

Answer 1

Answer:

x = (log 3 - log 2 ) / (log 3 + log 2)

Step-by-step explanation:

2^x+1 = 3^ 1-x

(x+1)log 2 = (1-x) log 3

(x+1)/(1-x)= log 3 / log 2

2/2x = (log 3 +log 2) / (log 3 - log 2)

x = (log 3 - log 2) / (log 3 +log 2)