Question

If 2^x+1 = 3^1-x then find the value of x.​

Answer 1

Answer:

2

x+1

=3

−x

taking log both side

(x+1log2=(1−x)log3

x=

log1+log3

log3−log2

Answer 2

Log[ 2^( x + 1 ) ] - Log[ 3^( 1- x ) ] = 0 Equation(2).

Rearranging Equation(2).

( x + 1 )/( 1 - x )

= 1.584962501 Equation(3).

Therefore x as calculated is correct.