If 2^x + 1 = 3^1-X, then find x.
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2^(x+1) =3^(1-x)
taking log both side
(x+1)log2=(1−x)log3
xlog2+log2=log3-xlog3
xlog2+xlog3 = log3-log2
X=(log3-log2)/(log2+log3)
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