if 2^x+1+4^x=8 then
find x
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Step-by-step explanation:
2^x+1 + 4^x = 8
2^x+1 + {(2)^2}^x = 8
2^x+1 + (2)^2x = 8
2^x+1 + (2)^2x = (2)^3
As the bases are same we will add the powers
x+1 + 2x = 3
x + 2x + 1 = 3
3x + 1 = 3
3x = 3 - 1
3x = 2
x = 2/3
Hope it helps you!!
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