If 2 x 10^22 atoms of N are removed from 20 g of N-atom, then find the mole of N-atom remained
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firstly found the mole for 20gm N atom so mole =20/14 , mole =1.428, then calculate no. of atom for N ,. no. of N-atom = mole× avagadro no. no. of atom = 1.428×6.02×10^23, after solving no. of N-atom is 8.6×10^23(86×10^22). and we remove 2×10^22 atoms so remaining atoms are 86×10^22 - 2×10^22 = 84×10^22 (8.4×10^23). we calculated remaining atoms of N then calculate the mole of remaining atoms is. 8. 4×10^23=mole×6.02×10^23,. mole 8.4×10^23/6.02×10^23 after solving mole of N atom remaining is 1.395. hope I am right and you got your answer
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