If 2^x^2 =3^y^2 = 12^z^2 then
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Answer:
Let 2x=3y=12z=r. Then
2=r1/x,3=r1/y, and 12=r1/z.
Since 12=22⋅3,
r1/z=r2/x⋅r1/y,
or
2x=1z−1y=y−zyz .
Thus x=2yzy−z. ■
Step-by-step explanation:
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