Math, asked by reeva06, 9 months ago

if 2^x - 2^x-1 =16, then the value of x^2 is??​

Answers

Answered by Anonymous
2

Step-by-step explanation:

2^x - 2^x / 2 = 2^4

2^x ( 1 - 1/2 ) = 2^4

2^x ( 1/2 ) = 2^4

2^x = 2^5

x = 5

Then x² = 5² = 25

Answered by chaitanyanagidi
0

Answer:

x= 5

Step-by-step explanation:

2^x-1 = 2^x / 2

2^x - ( 2^x/2)

( 2^x) ×(1 - 0.5)

( 2^x )× 0.5 = 16

2^x = 32

x=5

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