Math, asked by mahimhayat18, 6 days ago

if 2^x+³=32, then what is the value of 3⁶-^x​

Answers

Answered by ButterflyLife9090
0

Step 1:

First find the value of x, so If 2⁵=32, and 2+3 =5

Then we can say that, x=2 and x+3=5, so 2⁵=32

Step 2:

Now, we have found out that x=2, so If we put the value of x in equation 2 ( 3⁶-^x ), then 6-2=4 and 3⁴=81, so the value of 3⁶-^x = 81.

Solved!

Answered by sayantan735
0

Answer:

 {3}^{6 - x}  = 81

Step-by-step explanation:

 {2}^{x + 3}  = 32

Converting the base to 2 —

 {2}^{x + 3}  =  {2}^{5}

Since bases are equal, exponents are equal too —

x + 3 = 5

x = 2

So,

 {3}^{6 - x}  =  {3}^{(6 - 2)}  =  {3}^{4}  = 81 \: \:  \:  (ans)

Hope this helps you :)

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