Question

if 2^x+3=4^x-1 then value of x is​

Answer 1

Answer:

2^x+3 = 4^x-1

2^x+3 = 2²^x -1

2^x = y

y+3= y²-1

-y²+y+3+1 = 0

-y²+y+4 = 0

y²-y-4 =0

y = -b+/-√b²-4ac/2a

y = 1+/-√1²-4×1×-4 /2×1

y = 1+/- √17/2

y = 1+√17 /2

y = 1-√17 /2

2^x = (1+√17) / 2

x = ln{(1+√17)/2}/ ln(2)

2^x = (1-√17) / 2

x = ln{(1-√17)/2 }/ ln(2)

Answer 2

Answer:

2^x=4

Step-by-step explanation:

2^x+3=4^x-1

=>2^x-4^x= -1-3

=>-2^x=-4

=>2^x=4