Question

If 2^x=3^-x then what is the value of x

Answer 1

${2}^{x} = {3}^{ - x} \\ {2}^{x} = \frac{1}{ {3}^{x} } \\ {2}^{x} \times {3}^{x} = 1 \\ {(2 \times 3)}^{x} = 1 \\ {6}^{x} = 1 \\ {6}^{x} = {6}^{0} \\ x = 0$
Therefore x =0.

Answer 2

$\sqrt{552}$