if 2 X + 3 Y = 12 and xy = 6 find the value of 8 x cube + 27 y cube
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4
Answer is in pic answer is solved acc to equations formed
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Answered by
3
Given
2x+3y=12
xy=6
The factors of 6 are ,.... 1,2,3,6
so
we cannot take 1,6
so
we the 2,3
2 into 2 equals 4
3 into 3 equals 9
4 plus 9 is not equal to 12
so
we take it the other way
let x be 3
let y be 2
2 into 3 equals 6
3 into 2 equals 6
6 plus 6 equals 12
xy equals 6
that is 3 into 2 equals 6
now
8x^3 + 27y^3
8*x*x*x+27*y*y*y
216 X 216
46,656
Answered by
1
Given
2x+3y=12
xy=6
The factors of 6 are ,.... 1,2,3,6
so
we cannot take 1,6
so
we the 2,3
2 into 2 equals 4
3 into 3 equals 9
4 plus 9 is not equal to 12
so
we take it the other way
let x be 3
let y be 2
2 into 3 equals 6
3 into 2 equals 6
6 plus 6 equals 12
xy equals 6
that is 3 into 2 equals 6
now
8x^3 + 27y^3
8*x*x*x+27*y*y*y
216 X 216
46,656
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