Question

if 2^x=3^y=5^z=2160 find xyz​

Answer 1

Answer:

Given,

2x×3y×5z=2160, 

2160=2×2×2×2×3×3×3×5

2160=24×33×51

by comparision, we get,

x=4,y=3,z=1

3x×2−y×5−z

=34×2−3×5−1

=23×534

=4081

Answer 2

Answer:

369.1936

Step-by-step explanation:

Given 2^x=3^y=5^z=2160

then x=log(2160)/log(2)=11.076

then y=log(2160)/log(3)=6.988

then z=log(2160)/log(5)=4.770

thus xyz=11.076*6.988*4.770=369.1936