Question

if 2/x + 3/y = 6 and 1/x + 1/2x = 2 then find x and y​

Answer 1

Step-by-step explanation:

$\frac{2}{x} + \frac{3}{y} = 6$

$\frac{1}{x} + \frac{1}{2x} = 2$

Let

$\frac{1}{x} = p$

and

$\frac{1}{y} = q$

Value p and q put in equation above we

get.

$2p + 3q = 6$

$p + \frac{q}{2} = 2$

$p = 2 - \frac{q}{2}$

Value p put in equation above

$2 (2 - \frac{q}{2} ) + 3q = 6$

$2( \frac{2 - q}{2} ) + 3q = 6$

$2 - q + 3q = 6$

$2q = 6 - 2$

$q = \frac{4}{2}$

q = 2

Value of q put in equation above

$p = 2 - \frac{q}{2}$

$p = 2 - \frac{2}{2}$

$p = 2 - 1$

p = 1

$\frac{1}{x} = p$

$\frac{1}{x} = 1$

X = 1

And

$\frac{1}{y} = q$

$\frac{1}{y} = 2$

Y = 1/2

• I hope it's help
• Please Mark brainliest
• Thanks