if 2^x=3^y=6^-z find the value of 1/x+1/y+1/z
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0 is the answer of Ur question
take 2^x=k then 2=k^1/x
take 3^y=k then 3=k^1/y
take 6^-z=k then 6=k^-1/z
now by comparing all of equation we get answer is zeo
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