Question

If 2^x = 3^y = 6^-z, show that : 1/z = 1/y+2/x. Without using log
(And please don't spam, it's mean)

Answer 1

Answer:

2x=3y=6−z=k (Let)

So,

2=k1/x,  

3=k1/y and

6=k−1/z  

Since,

2×3=6  

⟹k1/x×k1/y=k−1/z  

⟹k1/x+1/y=k−1/z  

Since k is not 0

⟹1/x+1/y=−1/z  

1/x+1/y+1/z=0

I hope it helps you

Im not able to solve futher