Question

If 2^x= 3^y = 6^z, show that z = XY/x+y​

Answer 1

Step-by-step explanation:

refer to the picture

2^x=3^y=6^z=k(say)

2=k^1/x,3=k^1/y,6=k^1/z

2*3=6

k^1/x*k^1/y=k^1/z

k^(1/x+1/y)=k^1/z

1/x+1/y=1/z

(x+y) /xy=1/z

z=xy/(x+y)