If 2^x=3^y=6^z then prove that z=xy÷x+y
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2^x=3^y=6^y=k
2=k^1/x
similarly 3=k^1/y and 6=k^1/z
2×3=k^1/z
1/x +1/y=1/z
y+x/xy=z
hence proved
2=k^1/x
similarly 3=k^1/y and 6=k^1/z
2×3=k^1/z
1/x +1/y=1/z
y+x/xy=z
hence proved
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