Question

if 2^x=3^y=6^z then prove1/x +1/y-1/z =0 or z=xy/x+y​

Answer 1

Step-by-step explanation:

Let:

Then:

2 = k^{1}{x}

We know that,

i) 3 × 2 = 6

ii) xᵃ × xᵇ = xᵃ⁺ᵇ

Then,

Now, Substitute value of 3, 2,& 6.

The bases are equal .

So,

→

→

Hence proved.

hope this helps......