Question

If 2^x = 3^y = 6^z then z = ?
(1) x+y/xy
(2) ху/ x + y
(3) 2xy
(4) x/y​

Answer 1

let k be a constant

2^x =k => 2 = k^1/x

3^y =k => 3 = k^1/y

6^z =k => 6 = k^1/z

6=3×2

k^1/z = k^1/x × k^1/y

1/z =1/x+1/y

z= xy/x+y

answer: 2