if 2^x=3^y=6^z then z=
(1)x+y/xy (2)xy/x+y (3)2xy (4)x/y
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Correct option is C)
Given,
2
x
×3
y
×5
z
=2160,
2160=2×2×2×2×3×3×3×5
2160=2
4
×3
3
×5
1
by comparision, we get,
x=4,y=3,z=1
3
x
×2
−y
×5
−z
=3
4
×2
−3
×5
−1
=
2
3
×5
3
4
=
40
81
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