Question

If 2 X + 3 y equal to zero and 4 x minus 3 y = 20 then X + y equal
A----- 0
B----- 2
C------ 1
D-----3

Answer 1

Answer:

X + Y = 10/9

Step-by-step explanation:

In the attachment.

Answer 2

Answer:

Two equations are as follows

2x+3y=0................(1)

4x-3y=20................(2)

First we have to multiply equation (1) with the LCM of cofficient of the X of both equations✓

So as to get the same cofficient of X so as to find that both get cancelled✓

Which is as follows:-

$eq(1) \times 2 \\ \\ = > 2 \times 2x + 3y \times 2 = 0 \times 2 \\ = > 4x + 6y = 0$

$and \: eq \: (2) \times 1 \\ \\ = > 4x - 3y = 20$

Now

$4x + 6y = 0 \\ 4x - 3y = 20 \\ - - - - - - - - \\ 9y = - 20 \\ \\ = > y = -20/9</p><p>Now</p><p> <strong>by</strong><strong> </strong><strong> </strong><strong>putt</strong><strong>ing</strong><strong> </strong><strong> </strong><strong>the</strong><strong> </strong><strong> </strong><strong>v</strong><strong>alue </strong><strong> </strong><strong>of</strong><strong> </strong><strong> </strong><strong>y</strong><strong> </strong><strong> </strong><strong>in</strong><strong> </strong><strong> </strong><strong>equa</strong><strong>tion</strong><strong> </strong><strong>(</strong><strong>1</strong><strong>)</strong><strong> </strong><strong>we</strong><strong> </strong><strong> </strong><strong>get</strong><strong> </strong><strong> </strong><strong>the</strong><strong> </strong><strong> </strong><strong>value</strong><strong> </strong><strong>of </strong><strong>X</strong><strong> </strong><strong>✓</strong></p><p></p><p><strong>[tex]y = \frac{</strong><strong>-</strong><strong>20}{</strong><strong>9</strong><strong>} </strong><strong> </strong><strong>\\ \\ = > putting \: in \: eq(1)</strong><strong> </strong><strong> \</strong><strong>\ \\ = > 2x + 3 \times \frac{</strong><strong>-</strong><strong>20}{</strong><strong>9</strong><strong>} = 0 \\ \\ = > 2x </strong><strong>-</strong><strong> </strong><strong>2</strong><strong>0</strong><strong>/</strong><strong>3</strong><strong> = 0</strong><strong> </strong><strong> \\ \\ = > </strong><strong>6</strong><strong>x = </strong><strong>2</strong><strong>0</strong><strong> </strong><strong>=</strong><strong>X=</strong><strong>1</strong><strong>0</strong><strong>/</strong><strong>3</strong></p><p></p><p></p><p>A/Q</p><p></p><p></p><p></p><p><strong> </strong><strong>the</strong><strong> </strong><strong>value</strong><strong> </strong><strong>of</strong><strong> </strong><strong> </strong><strong>X</strong><strong>+</strong><strong>Y</strong><strong> </strong><strong>is</strong><strong> </strong><strong>as</strong><strong> </strong><strong>follows✓</strong></p><p></p><p><strong>[tex]x + y = 1</strong><strong>0</strong><strong>/</strong><strong>3</strong><strong> + \frac{</strong><strong>-</strong><strong>20}{</strong><strong>9</strong><strong>} \\ \\ = > \frac{ 30 </strong><strong>-</strong><strong> 20}{</strong><strong>9</strong><strong>} \\ \\ = > \frac{ 10}{</strong><strong>9</strong><strong>}$

So the value of X+Y is -10/3✓